If the length of a chord of a circle is 16cm and is at a distance of 15cm from the centre of the circle then find the radius of the circle
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Step-by-step explanation:
In the diagram AB is the given chord of 16 cm length and OM is the perpendicular distance from the centre to AB.
We know that perpendicular from the centre to any chord divides it into two equal parts.
Now consider right triangle OMA and by using Pythagoras theorem
162
AM
MB
= 8 cm.
So,
= 64+225
= 289
=289
=82+152
AO2=AM2+OM2
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