If the length of a metal wire of resistivity R is doubled and it's area is reduced to half. What would be the resistivity of the new wire.
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Explanation:
For the first wire R1- (rho) l/A = x ohm.
Now for the second wire,
R2- (rho) 2l/ 0.5A= 4 (rho) l/A
Therefoe R2 - 4 x ohm.
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