Question

If the length of a rectangle is 2 ft longer than its width. If the perimeter of the rectangle is 56 ft, find its length and width​

Answer 1

Answer:

l = w + 2

2l + 2w = 40 (perimeter)

Now plug in a solve.

2(w+2) + 2w = 40

2w + 4 + 2w = 40

4w=36

w=9

l = 9+2

l=11

Answer 2

Answer:

width=x=13ft

length=x+2=13+2=15ft

Step-by-step explanation:

Let the width be x

so, length= x+ 2

A/Q

Perimeter of rectangle= 56ft

2(l+b)=56ft

2( x + x+2) =56

2(2x+2)=56

4x+4=56

4x=56-4

x= 52÷4

x=13