Question

if the length of a rectangle is 3 more than thrice of its breadth and its perimeter is 54 then the area will be​

Answer 1

Answer:

let we assume

breadth =x

length=3x+3

perimeter of rectangle =2(l+b)

2(x+3x+3) =54

2(4x+3)=54

8x+6=54

8x=54-6

8x=48

x=48/8

x=6

hence

breadth =6

length = 21

Answer 2

Answer:

Length = 21 and Breadth = 6

Step-by-step explanation:

Let the breadth(b) of the rectangle be x.

Then, length(l) = (3x+3)

Now,

Perimeter =2(l+b)

54=2[(3x+3)+x]

54=2[3x+3+x]

54=2[4x+3]

54=8x+6

54 - 6=8x

48=8x

x=48/8

x=6

So, x=6,then length = 3x+3

=3×6+3= 21 (Ans.)

and breadth = x = 6 (Ans.)