Math, asked by JanhaviSinha, 1 month ago

If the length of a rectangle is decreased by 5 units and its breadth increased by 2 units then the area of the rectangle decreases by 80 square units. If its length is increased by 10 units and its breadth decreased by 5 units then the area of the rectangle increases by 50 square units. Find the original length and breadth of the rectangle.​

Answers

Answered by snehitha2
7

Answer:

The length of the rectangle is 40 units and the breadth is 30 units.

Step-by-step explanation:

Let the length of the rectangle be l units and the breadth be b units.

Area of the rectangle = length × breadth

Area of the rectangle = lb sq. units

According to the first condition,

Length = (l - 5) units

Breadth = (b + 2) units

Area decreases by 80 sq. units.

Area = (lb - 80) sq. units

(l - 5)(b + 2) = lb - 80

l(b + 2) - 5(b + 2) = lb - 80

lb + 2l - 5b - 10 = lb - 80

2l - 5b - 10 = -80

2l - 5b = -80 + 10

2l - 5b = -70

2l = -70 + 5b

l = (-70 + 5b)/2

l = -35 + 2.5b --(1)

According to the second condition,

length = (l + 10) units

Breadth = (b - 5) units

Area of the rectangle increased by 50 sq. units

Area = (lb + 50) sq. units

(l + 10)(b - 5) = lb + 50

l(b - 5) + 10(b - 5) = lb + 50

lb - 5l + 10b - 50 = lb + 50

10b - 5l = 50 + 50

10b - 5l = 100

2b - l = 20

2b - (-35 + 2.5b) = 20

2b + 35 - 2.5b = 20

-0.5b = -35 + 20

-0.5b = -15

0.5b = 15

b = 15/0.5

b = 30 units

Length, l = -35 + 2.5b

l = -35 + 2.5(30)

l = -35 + 75

l = 40 units

Therefore, the length of the rectangle is 40 units and the breadth is 30 units.

Answered by AllenGPhilip
0

Answer:

Step-by-step explanation:

Let the length of the rectangle be l units and the breadth be b units.

Area of the rectangle = length × breadth

Area of the rectangle = lb sq. units

As per the question

Length = (l - 5) units

Breadth = (b + 2) units

Area decreases by 80 sq. units.

Area = (lb - 80) sq. units

(l - 5)(b + 2) = lb - 80

l(b + 2) - 5(b + 2) = lb - 80

lb + 2l - 5b - 10 = lb - 80

2l - 5b - 10 = -80

2l - 5b = -80 + 10

2l - 5b = -70

2l = -70 + 5b

l = (-70 + 5b)/2

l = -35 + 2.5b --(1)

According to the second condition,

length = (l + 10) units

Breadth = (b - 5) units

Area of the rectangle increased by 50 sq. units

Area = (lb + 50) sq. units

(l + 10)(b - 5) = lb + 50

l(b - 5) + 10(b - 5) = lb + 50

lb - 5l + 10b - 50 = lb + 50

10b - 5l = 50 + 50

10b - 5l = 100

2b - l = 20

2b - (-35 + 2.5b) = 20

2b + 35 - 2.5b = 20

-0.5b = -35 + 20

-0.5b = -15

0.5b = 15

b = 15/0.5

⇒b = 30 units

Length, l = -35 + 2.5b

= -35 + 2.5(30)

= -35 + 75

= 40 unit

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