If the length of a rectangle is reduced by 50% and the breadth is increased by 25%, it takes the
shape of a square. Find the ratio of the areas of the rectangle and the square, and the perimeters of the rectangle and the square.
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for the rectangle let :
length =x and breadth=y
the area of the rectangle (A) : A=x*y
the perimeter of the rectangle (P): P=(x+y)*2
then for the square
length =(1-.5)*x = .5x and breadth=(1+.25)*y=1.25y
the area of the square (A')= .5x * 1.25y = .625 x*y
the perimeter of the square (P')=.5 *x*4 =2x
the ratio of the area of the rectangle and the square =1.6
the ratio of the perimeter of the rectangle and the square = x+y/x
∵ .5x=1.25 y
∴y = .4x
∴the ratio of the perimeter of the rectangle and the square =1.4
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