Question

solve the following quadratic equation x²-(3√2+2i)x+6√2i=0 ​

Answer 1

Answer:

x² - (3√2 – 2i)x - 6√2i = 0

x² - 3√2x + 2ix - 6√2i = 0

x(x - 3√2) + 2i(x - 3√2) = 0

(x + 2i)(x - 3√2) = 0

x = -2i or x = 3√2 ■