Question

if the length of a rectangular field is double of its bread the if perimeter is 66cm then find the area of the field?​

Answer 1

Answer:

Perimeter of rectangle = 2(l+b)

Here,

Let the breadth = x

Length =2x

So,

perimeter of rectangle= 2(x+2x)

→ 66 = 2x + 4x

→ 66 = 6x

→ x = 66/6

→x =11

So, Breadth of rectangle= 11cm

Length =22

So area of rectangle = l×b

=22×11

= 242 cm²

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Answer 2

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• Area of rectangular field = 242cm²

Step-by-step explanation:

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• Length of the rectangular field Is double of its breadth.

• Perimeter = 66cm

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• Area of the field .

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• Let the Breadth be x

• So, Length = 2x

• Given perimeter = 66

• Now, find the perimeter of the rectangular field .

• Perimeter = 2( Length + Breadth)

• Now, substitute the value If perimeter, Length, Breath in the equation.

• 66 = 2 ( 2x + x)

• 66 = 2 × 3x

• 66 = 6x

• x = $\bf \frac{66}{6}$

• $\boxed {\bf{\underline{ x = 11 cm} }}$

Length = 2x = 2 × 11 = 22cm

Breadth = x = 11 cm

• Now, Inorder to find the Area we use the Formula

• Area = Length × Breadth

• Area = 22 × 11

• $\boxed{\sf Area =242 cm^2 }$

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• Area of square = Side × Side

• Perimeter of square = 4 × Sides

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1)The length and breadth of a rectangle are 4.5 m and 175 cm respectively. Find:

(i) Perimeter of the rectangle (ii) Area of the rectangle

the

Answer in :- https://brainly.in/question/31728124

2) The length of a rectangle is 75 cm. its petimeter is 200 cm. find its area.

Answer in :- https://brainly.in/question/32228349

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