Question

if the length of a room is decreased by 10% and breadth is decreased by 20% while height is increased by 5% then what percentage change in the volume of the room​

Answer 1

Answer:

$x {.2.1y22 = 02 \times 14y {41 {211}^{2} }^{.9} 1.1}^{2}$

Answer 2

Answer:

31.42%

Step-by-step explanation:

Given : length of a room is decreased by 10% and breadth is decreased by 20% while height is increased by 5%

Length  old        new

              10            9

Breadth 5              4

Height   21            20

Volume 10×5×21      9×4×20

            1050              720

Therefore percentage change in the volume of the room​

= (1050-720)/1050×100

= (330/1050)×100

= 31.42%