Question

If the length of a seconds pendulum is increased by 2

Answer 1

T = 2π √(L/g)

ΔT / T * 100 = 1/2 * ΔL/L * 100

                   = 1/2 * 2% = 1%

Time period increases by 1% =>

So one second becomes  1.01 seconds.  The pendulum loses 0.01 sec.

In one day of 86400 seconds,  the clock loses 864 seconds. or 144 minutes or 2 hours 24 minutes........