if the length of a simple pendulum is doubled what will be the change in its time period?
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Period of a simple pendulum is given by T = 2pi times the square root of( l/g)
where T = period (s) l = length (m ) g = gravity (m/second squared)
From this relationship, it can be seen that if l is doubled, the increase in period is square root of 2 times the original period, i.e. 1.414 times the original period
Explanation:
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