if the length of a square is decreased by 7cm , its area
decreases by 259 cm2
, what was the original length of the
square?
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Answer:
22 cm
Step-by-step explanation:
Let the original length of the square be 's'.
Original area of square=s*s
Now, New length of square=(s-7)cm
New area of square=(s-7) ^2
A.T.P,
s^2=(s-7)^2 + 259
=> s^2=s^2 + 49 - 14s +259
=> 14s= 308
=> s= 308/14
=> s=22 cm (ans)
Therefore, the original length of square is 22cm.
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