Math, asked by zendegaurav2512, 2 months ago

if the length of diagonals of a rhombus is 16and12 cm the side of rhombus is​

Answers

Answered by vinshultyagi
125

{\Huge {\fbox{\bf {\red{Given:-}}}}}

The length of the first diagonal is 12 cm, whereas the length of the second diagonal is 16 cm.

{\Huge {\fbox{\bf {\green{To\:Find:-}}}}}

The sides of Rhombus

{\Huge {\fbox{\bf {\green{Solution:-}}}}}

Now as we know that BD = 16 cm and AC = 12 cm; therefore to find S

We use,

\bf \left(\dfrac{B D}{2}\right)^{2}+\left(\dfrac{A C}{2}\right)^{2}=S^{2}

\bf \left(\frac{16}{2}\right)^{2}+\left(\frac{12}{2}\right)^{2}=S^{2}

\bf (8)^{2}+(6)^{2}=S^{2}(8)

\bf \sqrt{100}=S

\bf  S=10cm

\therefore {\bold{\underline{Side\:of\:rhombus\:is\:10cm}}}

Answered by Anonymous
1

Answer:

Diagonals of rhombus are cut each other at 90

Since d ¹ =16and d ² =12

Therefore, by Pythagoras theorem

a ² = (d¹/2)² + (d² /2)²

⇒ a ² =8 ² +6 ²

⇒ a= 100 =10

Step-by-step explanation:

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