If the length of DNA is 68A then what will be the number of nucleotides present in it?
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Given :- Length of DNA = 68 A°
( Dna stand has 68 × 3.4 = 20 base pair )
Note :- 1 Base pair = 2 Base , like Base are found in DNA: adenine (A), thymine (T), cytosine (C), and guanine (G).
where ,
- adenine forming a base pair with thymine
- cytosine forming a base pair with guanine
We know :- 4 nucleotides = 2 Base pair
so,
40 nucleotides = 20 base pair
Here, 68 × 3.4 = 20 base pair = 40 Nucleotides
"The number of nucleotides present in Dna is 40"
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