Question

if the length of e. coli DNA is 1.36 mm, can u calculate the nmbr of base pairs in e. coli?

Answer 1

The distance between a bp is 0.34nm
So no of base pairs are 1.36mm / 0.34nm
It is equal to 4.6 × 10^6 (approx).
I hope it will help u..

Answer 2

Distance between two consecutive base pair = 0.34 nm

Total length of given DNA = 1.36mm  

∴ total no. of base pair =  1.36mm /0.34nm

⇒ 4 × 10⁶ Base pair.