Question

If the length of each edge of a cube is double, how many times does it's volume become? How many times does it surface area become.


solve this plz ​

Answer 1

Step-by-step explanation:

1) let the edge of the cube = a units

volume=v=a3---(1)

surface area=6a^2 square units---(2)

2)if length of each edge doubled

the new cube edge = 2a units

volume = V= (2a)^3=8a^3

= 8×(1)

=8 times of the first cube volume

3) surface area = A= 6*(2a)^2

=6×4×a^2

=4×(6a^2)

=4×(2)

=4 times of the first cube

Answer 2

$\large\underline\pink{Given:-}$

• the length of each edge of a cube is double

$\large\underline\pink{To find:-}$

• Find how many times does it's volume become?
• How many times does it surface area become.. ....?

$\large\underline\pink{Solutions:-}$

• Let a be the length of the edge of a cube.

Volume of the cube = a²

Total surface area = 6a²

if the length is doubled, then the new length become 2a.

Now,

new Volume = (2a)³

= 8a³

also, new surface area

= 6(2a)²

= 6 × 4a²

= 24a²

the volume is increased by a factor of 8, while the surface area increase by a factor of 4.

$\large\underline\pink{more \: \: important:-}$

• volume of cube = a³
• surface area of cube = 6a²

Properties of Cube:-

1. Each of the faces meets the other four faces.
2. Each of the vertices meets the three faces and three edges.
3. The edges opposite to each other are parallel