Question

If the length of each edge of a cube is doubled, by how many times does its volume and surface area increase?

Answer 1

1) let the edge of the cube = a units
volume=v=a3---(1)
surface area=6a^2 square units---(2)
2)if length of each edge doubled
the new cube edge = 2a units
volume = V= (2a)^3=8a^3
= 8×(1)
=8 times of the first cube volume
3) surface area = A= 6*(2a)^2
=6×4×a^2
=4×(6a^2)
=4×(2)
=4 times of the first cube

Answer 2

Step-by-step explanation:

1) Let the edge of the cube =9 units

Volume = v= a^3

surface area = 6^2

2) If lenght of each edge doubled the new cube edge = v (2a)^3 =8a^3

=8×(1)

= 8 times of the first cube volume

3) Surface=A=6*(2a)^2

=6×4×a^2

=4×(6a^2)

=4×2

4 times of the first cube

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