Question

If the length of rectangle is 12cm and breadth is 20cm wo find it's Perimeter and Area both?

Answer 1

perimeter of rectangle=2(l+b)

=2(12+20)

=64cm

Area of rectangle=l×b

12×20

240

hope it helped you

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Answer 2

Given

• $\sf {Length} \mapsto$ 20cm
• $\sf {Breadth} \mapsto$ 12cm

To find

• The Area and the Perimeter

Solution

${ \underline{ \underline{ \boxed{ \bf{Understanding \: the \: question}}}}}$

In the Question it has given the Length and the Breadth of the Rectangle and we have to find the Area and the Perimeter of it So, to find it we have to use the formula to solve it after using formula we will get the whole answer

${ \dag}{\underline{ \mathfrak{ \purple{As \: we \: know \: that}}}}$

$\;\boxed{\sf{\purple{Area_{\:(rectangle)} = Length \times Breadth}}}$

$\;\boxed{\sf{\pink{Perimeter_{\:(rectangle)} = 2 \times Length + Breadth}}}$

${ \underline{ \underline{ \red{ \mathfrak{According \: the \: question}}}}}$

First, let's find the Area

$: \implies$ Length $: \leadsto$ 12cm Breadth

$: \implies$  $\sf{{12_{\:(cm)}} × {20_{\:(cm)}}}$

$: \implies$ ${ \underline{ \boxed{ \pink{ \mathfrak{{240_{\:( {cm}^{2} )}}}}}}}$

Now, let's find the Perimeter

$: \implies$ Length $: \leadsto$ 20cm Breadth

$: \implies$  $2× \sf{{12_{\:(cm)}} + {20_{\:(cm)}}}$

$: \implies$ $\sf{2 × {32_{\:(cm)}}}$

$: \implies$ ${ \underline{ \boxed{ \pink{ \mathfrak{{64_{\:(cm)}}}}}}}$

•°• Hence, verified! that the Perimeter is 64cm and the Area is 240 $\sf{cm}^{2}$

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Diagram

Here is the diagram of Rectangle to understand more about Perimeter and Area

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 20 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 12 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

[Note:- Kindly see the diagram in the web page or see the attachment :) ]

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