If the length of rectangle is increased by 10% and the area is un changed then its corresponding breadth must be decreased by
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Let the length and width be a and b respectively
Area = ab
New Length = a + 10a/100 = 11a/10
Now,
New area = ab
=> 11a/10 × New width = ab
=> New Width = 10b/11
Decrease in width = b - 10b/11
Decrease in width = b/ 11
Percentage of Decrease = ( 10b /11)× 100 /b %
= 100/ 11
= 9.09 %
Area = ab
New Length = a + 10a/100 = 11a/10
Now,
New area = ab
=> 11a/10 × New width = ab
=> New Width = 10b/11
Decrease in width = b - 10b/11
Decrease in width = b/ 11
Percentage of Decrease = ( 10b /11)× 100 /b %
= 100/ 11
= 9.09 %
Answered by
0
Let the length and width be a and b respectively
Area = ab
New Length = a + 10a/100 = 11a/10
Now,
New area = ab
=> 11a/10 × New width = ab
=> New Width = 10b/11
Decrease in width = b - 10b/11
Decrease in width = b/ 11
Percentage of Decrease = ( 10b /11)× 100 /b %
= 100/ 11
= 9.09 %
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