Question

if the length of the conductor and its radius is increased twice , how the resistance will change ?​

Answer 1

Answer:

resistance multiplies by 1/2 times.

Explanation:

We have  the formula of resistance

Resistance = Resistivity x length/area

So  here, length of conductor and its radius is twice

we know area = π $r^{2}$

then, new resistance will be

New Resistance = Resistivity x 2length/π$(2r)^{2}$

I.e,

New resistance = (Resistivity x length/2×area)

i.e, New resistance = Resistance / 2

So when the length of the conductor and its radius is increased twice, then resistance multiplies by 1/2 times.

Answer 2

twice or half is the right