Question

If the length of the conductor is doubled and area of cross section is halved the resistance of the conductor ..............................
(2 Points)
4 times increases
4 times decreaes
constant
1/2 times increases

Answer 1

Answer:

4 times increases

Explanation:

because r = l/a

so now R1= 2l/1/2a

R1= 2*2 l/a

R1= 4 l/a

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