Question

the ratio of the number of blocks of type a b c and d is 13 :21:4:15 if the no. of blocks of type b is 102 more than that of type c then what is the total no. of blocks​

Answer 1

Answer:

Total no. of blocks is 318

Step-by-step explanation:

Let the constant be x

Therefore,

• No. of blocks of a type = 13x
• No. of blocks of b type = 21x
• No. of blocks of c type = 04x
• No. of blocks of d type = 15x

To find :- Total no. of blocks.

Soln :-

according to the given condition,

$21x = 4x + 102$

.........(since the no. of blocks of type b is 102 more than that of type c)

$21x - 4x = 102 \\ 17x = 102 \\ x = \frac{102}{17} \\ x = 6$

Therefore, Blocks of type a

$13x = 13 \times 6 \\ 13x = 78$

blocks of type b

,

Similarly,

$21x = 21 \times 6 \\ 21x = 126$

Blocks of type c

$4x = 4 \times 6 \\ 4x = 24$

blocks of type d

$15x = 15 \times 6 \\ 15x = 90$

Therefore,

Total blocks are

$= 78 + 126 + 24 + 90 \\ = 318 \: blocks$

Ans:-

Total no. of blocks is 318

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