Question

if the length of the conductor is doubled and area of cross section is halved the resistance of conductor

Answer 1

Resistance increases 4times 4x

Answer 2

The new resistance of the conductor is 4 times that of the initial resistance.

Explanation:

The resistance of the conductor is given by :

$R=\rho \dfrac{L}{A}$

$\rho$ is the resistivity of the material

L is the length of the conductor

A is the area of cross section

If the length of the conductor is doubled and area of cross section is halved,

L' = 2L and A' = A/2

New resistance becomes,

$R'=\rho \dfrac{L'}{A'}$

$R'=\rho \dfrac{(2L)}{(A/2)}$

$R'=4\rho \dfrac{L}{A}$

$R'=4\times R$

So, the new resistance of the conductor is 4 times that of the initial resistance.

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