Question

if the length of the ladder placed against a wall is twice the distance between the foot of the ladder and the wall find the angle made by the ladder with the horizontal​

Answer 1

Step-by-step explanation:

Let, AB = x C = 2x In ΔABC ∠B = 90° cos A = x/2x cos A = 1/2 = cos 60° A = 60°

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Angle\:of\:elevation}=60^{\circ}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about the length of the ladder placed against a wall is twice the distance between the foot of the ladder and the wall.

• We have to find the angle of elevation.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\:ladder=2\:times\:Distance\:between\:wall\:and\:foot\:of\:ladder} \\ \\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Angle\:of\:elevation= ?}$

• Accroding to given question :

$\text{Let\:distance\:between\:ladder\:and\:wall\:be\:x} \\\\\bold{In \: \triangle \: ABC} \\ : \implies cos \: \theta = \frac{\text{Base}}{\text{Hypotenuse}} \\ \\ : \implies cos \: \theta= \frac{BC}{AC} \\ \\ : \implies cos\:\theta= \frac{x}{2x} \\ \\ : \implies cos\:\theta= \frac{1}{2} \\ \\ \green{ : \implies \theta= 60^{\circ}} \\ \\ \green{\therefore \text{Angle\:of\:elevation} = 60^{\circ}}$