Question

if the length of the median AP of AABC is 12 cm and G is the centroid, then find 1(AG) and 1(GP).​

Answer 1

Answer:

Step-by-step explanation:

AP is the median and G is the centroid.

So AG:GP=2:1

So AG=(2/3)×12=8cm

GP=12-8=4cm

Answer 2

Answer:

We know that G is centroid of ΔABC

AD=12cm

Centroid → intersection point of medians

Centroid divides median in ratio of 2:1

AD

AG

=

1

2

AG=2AD

AG+GD=12

3GD=12

GD=4cm

AG=8cm.