Question

x-y=2;3x+2y=16..find x and y ​

Answer 1

Answer:

1. x-y=2

multiplying 1. with 2

2x-2y=4

adding 1. and the other equation

2x-2y+3x+2y=4+16

5x=20

x=20

$20 \div 5$

x=4

Hope it helps you

Answer 2

Answer:

Step-by-step explanation:By elimination method

x-y=2

3x +2y=16.

3x+2y-16=0. eq2

x-y=2

Multiplying 3 on both sides

3x-3y=6.

3x-3y-6=0 eq1

Subtracting eq1-eq2

3x-3y-6-(3x+2y-16)=0

3x-3y-6-3x-2y+16 =0

-5y +10=0

-5y =-10

y=2

Putting value of your in eq 1

3x-3×2-6=0

3x -12=0

3x =12

x=4

Hence x=4

y=2

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