If the length of the perpendicular from the point (β, 0, β) (β = 0) to the line, x/1 = (y - 1)/0 = (z + 1)/-1 is,
√(3/2) then β is equal to:
(A) 1 (B) –1
(C) 2 (D) –2
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Answered by
0
Answer:
If the length of the perpendicular from the point (β, 0, β) (β = 0) to the line, x/1 = (y - 1)/0 = (z + 1)/-1 is,
√(3/2) then β is equal to:
(A) 1
(B) –1
(C) 2✔
(D) –2
Answered by
1
Answer:
If the length of the perpendicular from the point (β, 0, β) (β = 0) to the line, x/1 = (y - 1)/0 = (z + 1)/-1 is,
√(3/2) then β is equal to:
(A) 1 (B) –1
(C) 2 (D) –2
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