Question

if the length of the rectangle is 5 more than at's breadth x. What is the perimeter of the rectangle​

Answer 1

Answer:

If the length of the rectangle is 5 more than it's breadth x then the perimeter of the rectangle​ is $4x + 10 cm$.

Step-by-step explanation:

Given:

If breadth (b) = x

then the length of the rectangle (l) = x+ 5 m

Formula:

The perimeter of the rectangle​ = 2 ( l + b)

$= 2 (x + x+ 5)$

$= 2(2x + 5 )$

$= 4x + 10 cm$

Answer 2

In context to question asked,

We have to determine the perimeter of rectangle.

As we know that,

Perimeter of rectangle will be $=2(l+b)$

As per question,

We have,

if the length of the rectangle is 5 more than it's breadth x.

So, let the length of rectangle will be $=(x+5)\:Km$

So, putting the formula in above equation,

$Perimeter = 2(l+b)\\=>Perimeter = 2(x+x+5)\\=>Perimeter = 2(2x+5)\\=>Perimeter = 4x+10\:units$

Hence, perimeter of rectangle will be 4x+10 units.