Question

if the length of the simple pendulum becomes 2 times its time period will be??​

Answer 1

Answer:

2πis also a constant. Therefore we can say that time period is directly proportional to square root of length of the pendulum. Therefore as the length of the pendulum becomes four times, the time period becomes the 2 times.

Answer 2

Answer:

Explanation:

time period becomes two times of its initial.

it is given that length of a simple pendulum is increased to four times the initial length.

we know,

T = 2π√{l/g}

where I is length of pendulum, T is time period and g is acceleration due to gravity.

here g is constant i.e., g = 10m/s²

so, T & VI, therefore time period of simple pendulum is directly proportional to square root of its length.

if length of simple pendulum is increased to four times.i.e., L = 41

so, T₁/T₂ = √(1₁/12}

⇒ T/T₂2 = √{1/41} = 1/2

⇒ T₂ = 2T

hence time period becomes two times of its initial.