Question

If the length of the vernier scale is doubled by keeping the number of divisions the same , how does its least count vary?

Answer 1

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☞ It is double

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$\huge\sf\blue{Given}$

✭ Length of the vernier scale is doubled

✭ But the number of divisions is kept the same

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◈ How does the count vary?

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So as per the question, the length of the vernier scale is doubled and the number of VSD is kept the same

➝ (VSD) ′ = 2(VSD)

➝ 2 × 0.9

➝ 1.8 mm

But we know that,

N × VSD = (N-1) MSD

So if the value of N is 10,then

➳ 10 × 1.8 = (9) × 1 MSD

➳ 1 MSD ′ = (10/9) × 1.8

➳ 2 mm

Therefore LC ′ = 1 MSD ′ - 1 VSD ′

➠ 2 - 1.8

➠ 0.2 mm

So the new LC is double the original one

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