if the length of the wire is tripled and its area of cross section reduces to 5 times , if the initial resistance of the wire is 50 ohm . find the change in resistance of the wire
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Answer:
Let initial resistance = R
length = l
area of cross section = a
its resistivity = e
R = e * l/a
Let final resistance = R'
length = l' = l/3 since wire is tripled
area = a' = a*3 since wire is tripled
R' = e * l'/a'
R' = e * l/a*3*3
R' = e l/9a
R' 1/9 * el/a
but el/a = R
R' = 1/9 R
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