If the line 3x+4y-24=0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is
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Answer
Line intersects the x-axis at x=8,y=0
⇒A=(8,0)
Line intersects the y-axis at x=0,y=6
⇒B=(0,6)
Incenter of triangle OAB =(
a+b+c
ax
1
+bx
2
+cx
3
),(
a+b+c
ay
1
+by
2
+cy
3
)
Where O=(x
1
,y
1
)=(0,0),A=(x
2
,y
2
)=(8,0),B=(x
3
,y
3
)=(0,6)
⇒AB=10,OB=6,OA=8
⇒Incenter =(
10+8+6
10.0+6.8+8.0
,
10+8+6
10.0+6.0+8.6
)
⇒incenter =(2,2)
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