If the line joining the points (-1,-4) and (3,4) is a tangent to the circle whose centre is at origin then find the point of contact of the tangent
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answer is √-42
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The point of contact of the tangent on the circle is equal to (4/5 , -2/5).
The tangent is formed by joining the point (-1,-4) and (3,4) .
Slope of the line = m = (4+4)/(3+1) = 2
The equation of the tangent -
y - 4 = 2(x - 3)
=> y - 4 = 2x - 6
=> y = 2x - 2
The radius of the circle will be equal to the distance of the tangent from the center of the circle (origin) .
r = 2/√5
The equation of the circle -
x² + y² = 4/5
Put y = 2x - 2 in the equation of circle to get the point of contact
=> x² + (2x - 2)² = 4/5
=> x² + 4x² + 4 -8x = 4/5
=> 25x² - 40x +16 = 0
=> x = 4/5
y = 8/5 -2 = -2/5
The point of contact of the tangent is (4/5 , -2/5).
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