Question

If the line (x - 2)/3 = (y + 1)/2 = (z - 1)/1
intersects the plane 2x + 3y – z + 13 = 0 at a point P and the plane 3x + y + 4z = 16 at a point Q, then PQ is equal to : (A) 2√14 (B) 14
(C) 2√7 (D) √14

Answer 1

Answer:

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If the line (x - 2)/3 = (y + 1)/2 = (z - 1)/1

intersects the plane 2x + 3y – z + 13 = 0 at a point P and the plane 3x + y + 4z = 16 at a point Q, then PQ is equal to : (A) 2√14 (B) 14

(C) 2√7 (D) √14✔

Answer 2

Answer:

$\huge\boxed{\fcolorbox{black}{pink}{Hi mate!}}$

If the line (x - 2)/3 = (y + 1)/2 = (z - 1)/1

intersects the plane 2x + 3y – z + 13 = 0 at a point P and the plane 3x + y + 4z = 16 at a point Q, then PQ is equal to :

(A) 2√14

(B) 14

(C) 2√7

(D) √14✔