if the linear momentum of a body increases by 20% what will be percentage increase in kinetic energy
Answers
Answered by
6
KE = P² / 2m
K₁ / K₂ = (P₁/P₂)²
K₁ / K₂ = (100/120)²
K₁ / K₂ = 25 / 36
K₂ = 36 K₁ / 25
% increase in KE
= [(K₂ - K₁) / K₁] *100
= 11 x 100 / 25
= 44 % increase
Similar questions