Question

ph of an aqueous solution having 3.15g of HNO3 in 500ml of solution is​

Answer 1

Dilute soln Is the answer because it has less amount of hno3

Answer 2

The pH of the solution is 1

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:  

Given mass of nitric acid = 3.15 g

Molar mass of nitric acid = 63 g/mol

Volume of solution = 500 mL

Putting values in above equation, we get:  

$\text{Molarity of solution}=\frac{3.15\times 1000}{63\times 500}\\\\\text{Molarity of solution}=0.1M$

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions

To calculate the pH of the solution, we use the equation:

$[pH=-\log[H^+]$

Putting values in above expression, we get:

$pH=-\log (0.1)\\\\pH=1$

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