If the linear momentum of the object is increased by 0.1%, then the kinetic energy is increased by
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Answered by
1
Explanation:
K=√2 mp
p=1+0.1
=p=1.1
K=√2m*1.1
K1/K = √2mp/√2m*1.1
= 1/1.1
It increases by 1.1 times
Answered by
3
Answer:
heyy.........
momentum, p=mv.
v=√2E/m.
p=m√2E/m=√2mE.
taking log and then differentiating on both the sides, we get,
∆p/p=1/2(∆m/m)+1/2(∆E/E).
∆p/p=1/2×0.1=0.05.
hope it helps u!!
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