Question

if the liner momentum of a body increase by25 percentage . what i

Answer 1

Answer:

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Answer 2

Answer:

The relation between kinetic energy, K and momentum p is the following.

K=p^2/2m…………(1)

Since, body is the same, mass remains constant.

If momentum increases by 25%, then new momentum will be

p’=1.25 p. Hence, new kinetic energy will be K’=(1.25)^2p^2/2m……….(2)

Then, (K’-K)/K=[p^2/2m(1.25)^2–1)]/(p^2/2m)=[(1.25)^2–1]=1.56–1.=0.56

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Therefore % increase in kinetic energy=0.56x100=56%