if the lines 2my-3x=4 and 3my+8x=10 are perpendicular to each other find the value of m
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Answered by
3
First eq. =. 2my-3x =4
2my=3x+4
y= 3x/2m +4/2m
y=3x/2m + 2/m
m1 =3/2m 1.
second ea. =. 3my+ 8x =10
3my= -8x +10
y= -8x /3m + 10/3m
m2 = -8/3m
since line are perpendicular m1m2= -1
( 3/2m )(-8/3m)=-1
-24/ 6m^2= -1
-24 = - 6m^2
24 =. 6m^2
6m^2 = 24
m^2 = 24/6
m^2 = 4
m== 2 . m=2 ans.
i hope help me
2my=3x+4
y= 3x/2m +4/2m
y=3x/2m + 2/m
m1 =3/2m 1.
second ea. =. 3my+ 8x =10
3my= -8x +10
y= -8x /3m + 10/3m
m2 = -8/3m
since line are perpendicular m1m2= -1
( 3/2m )(-8/3m)=-1
-24/ 6m^2= -1
-24 = - 6m^2
24 =. 6m^2
6m^2 = 24
m^2 = 24/6
m^2 = 4
m== 2 . m=2 ans.
i hope help me
Answered by
2
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