Question

If the lines 2x+3y +1=0 and 3x-y -4 =0 lie along diameter of a circle of circumference 10pi , then the equation of a circle is . ​

Answer 1

Step-by-step explanation:

GIVEN:

Two lines 2x +3y+1 =0 and 3x-y-4 =0

》after solving two lines we get centre of circle

Now

According to question ,

diameter of circle is equal to = 10 pi

Then value of centre and radius put in

standard equation of circle

we know that

Standard equation of circle is .

$(x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$