Question

2x+5y=12
4x+3y=-4

do it using substitution method take y common from eq 2​

Answer 1

Answer:

2x + 5y = 12...eq.1

4x+ 3y = -4.....eq.2

taking value of x from eq.1

2x = 12-5y

x = (12-5y)/2

putting value in eq.2

4 x (12-5y)/2 +3y = -4

24-10y+3y = -4

24-7y = -4

7y = 28

y = 4

putting value in eq.1

2x + 5x4 = 12

2x = -8

x = -4

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Answer 2

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

1)

$\implies2x + 5y = 12 \\ \\ \implies5y = 12 - 2x \\ \\ \implies \: y = \frac{12 - 2x}{5}$

2)

$\implies4x + 3y = - 4$

${\large{\blue{\bold{\underline{Now,}}}}}$

▪︎ By putting the value of y in eq(2) we get:-

$\implies4x + 3( \frac{12 - 2x}{5}) = - 4 \\ \\ \implies4x + \frac{36 - 6x}{5} = - 4 \\ \\ \implies \frac{20x - 6x + 36}{5} = - 4 \\ \\ \implies14x + 36 = 5( - 4) \\ \\ \implies14x + 36 = - 20 \\ \\ \implies14x = - 20 - 36 \\ \\ \implies14x = - 56 \\ \\ \implies \: x = \frac{ - 56}{14} \\ \\ \implies \: x = - 4$

${\large{\blue{\bold{\underline{Again,}}}}}$

▪︎ Putting the value of x in the value of y we get,

$\implies \: y = \frac{12 - 2x}{5} \\ \\ \implies \: y = \frac{12 - 2( - 4)}{5} \\ \\ \implies \: y = \frac{12 - ( - 8)}{5} \\ \\ \implies \: y = \frac{12 + 8}{5} \\ \\ \implies \: y = \frac{20}{5} \\ \\ \implies \: y = 4$

☆ Therefore the required values of x and y are -4 and 4 respectively.