Question

If the lines 3x+2ky +2=0 and 2x+5y+1=0 have unique solution then find k

Answer 1

3x+2ky = -2 ; 2x+5y = -1

a1 = 3, b1 = 2k, c1 = -2

a2 = 2, b2 = 5, c2 = -1

a1/a2 = b1/b2 ≠ c1/c2 [Unique Solution]

3/2 = 2k/5 ≠ -2/-1

3×5 = 2k × 2

15 = 4k

15/4 = k

Hence, the value of K is 15/4

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