If the lines given by 3x+2ky= 2 and 2x +5y = -1 are parallel, then find the value of k
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Answered by
12
3x/2x = 2ky/5y
3/2= 2k/5
3×5=2×2k
15/4 = k
3/2= 2k/5
3×5=2×2k
15/4 = k
Anonymous:
wrong
Answered by
25
Hi friend,
Here is your answer,
_____________________________________________________________
3x + 2ky - 2 = 0 ; 2x + 5y + 1 = 0
a₁ = 3 a₂ = 2
b₁ = 2k b₂ = 5
c₁ = -2 c₂ = 1
For parallel lines :-
a₁ = b₁ ≠ c₁
a₂ b₂ c₂
3 = 2k ≠ -2
2 5 1
15 = k
4
k ≠ -5
_____________________________________________________________
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★★★★ PLS MARK ME AS BRAINLIEST ★★★★
Here is your answer,
_____________________________________________________________
3x + 2ky - 2 = 0 ; 2x + 5y + 1 = 0
a₁ = 3 a₂ = 2
b₁ = 2k b₂ = 5
c₁ = -2 c₂ = 1
For parallel lines :-
a₁ = b₁ ≠ c₁
a₂ b₂ c₂
3 = 2k ≠ -2
2 5 1
15 = k
4
k ≠ -5
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
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