If the lines given by
(k-3)x+3y=k
kx + ky= 12
are parallel, then the value of k is
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1
Answer:
no value
Step-by-step explanation:
If the lines are parallel, then
a1/a2 =b1/b2
or k-3/k = 3/k
or k-3 = 3
or k = 6
Also, c1/c2 should not be equal to a1/a2 and b1/b2
so, 6/12 but all 3 are equal, so there is no value
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