Question

If the lines kx-6y =0 and 6x+5y =13 are perpendicular to each other, then value of k is

9
5
-5
-7

Answer 1

Answer:

5

Step-by-step explanation:

if the two lines are perpendicular then a. b =0

k. 6 +(-6).5=0

6k - 30=0

6k =30

k=5

Answer 2

5

When two lines meet at 90 degree angle, then it is said to be perpendicular to each other. m is the slope of line. m1 is the slope of first line. m2 is the slope of second line. The product of m1 and m2 is -1.

Given equations,

kx-6y =0

6x+5y =13

These lines are perpendicular to each other.

Therefore, m1 m2= -1

The line equation is y= mx+c

1st equation,

kx-6y =0

-6y= -kx

  y= (k/6) x

m1 = k/6

2nd equation,

6x+5y =13

5y = -6x+13

 y = (-6/5)x+13/5

m2 = -6/5

m1 m2 = (k/6) (-6/5)= -1

Both 6 will get cancelled.

k/-5 = -1

k= -5 x -1 = 5

The value of k is 5.