Question

If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360. Find the original price of the toy.

Answer 1

SOLUTION :  

Let the original price of the book be ₹ x.

Number of books bought for ₹ 360 = 360/x  

Reduced list price of the book = ₹ (x - 2)

Number of books bought for ₹ 360 = 360/(x - 2)

A.T .Q

360/(x - 2) - 360/x = 2

360[1/(x -2) - 1/x ] = 2

[1/(x -2) - 1/x ] = 2/360

[x - (x - 2)] /x(x - 2) = 1/180

[By taking LCM]

(x - x + 2)/x² - 2x = 1/180

2/x² - 2x = 1/180

x² - 2x = 2 × 180

x² - 2x = 360

x² - 2x  - 360 = 0

x² - 20x + 18x - 360 = 0

[By middle term splitting]

x(x - 20) + 18(x - 20) = 0

(x - 20) (x + 18) = 0

(x - 20) = 0  or  (x + 18) = 0

x = 20 or x = - 18  

Since, the price of the book can't be negative, so x ≠ - 18  

Therefore , x = 20  

Hence, the original  price of the book is ₹ 20.

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

$\huge{Hey \ Dude}$

Here is your answer ✌✌

If the list price of a toy is reduced by Rs. 2

A person can buy 2 toys more for Rs. 360.

So the original price of the toy is



Let the p = original price 
x = number of toys 

px = 360 
p=360/x 

(p-2) (x+2) = 360
 
px +2p -2x -4 = 360 

360 + 2(360/x) -2x -4 = 360 

720/x - 2x -4 = 0 

720 - 2x^2 - 4x =0 

2x^2 + 4x -720 =0 

x^2 + 2x -360 =0 

(x + 20)(x - 18) = 0 

x = -20 and x = 18 

So, A negative number cannot be choose.

So, we have to choose A positive number.

So, X =18

px = 360 

p = 360/x = 360/18 

p = 20

So, The original Price of ths toy is Rs . 20

$\huge\bold{Hope \ Its \ Help \ You}$