Question

If the magnetic field is parallel to the positive y-axis and the charged particle is moving along the positive x-axis, which way would the lorentz force be for a proton ?

Answer 1

Force is given by:F = q(v×B)velocity is along x −axis = iˆmagnetic field is along y − axis = jˆforce on  the proton will be along z axis i.e. kˆ

$hope \: helps$

Answer 2

Answer:

The Lorentz magnetic force is given by

F = q (V X B) there is no vector sign but read this equation as vector equation

for a proton q = 1.6 * 10^-19 which is positive

F = q[V(x) X B(y) ]

Consider the right hand co-ordinate system

The cross product between x and y unit vectors is z in the positive side .

so the force will be the positive z direction .

For an electron the the charge value will be negative and hence the direction of force rotates by 180 degrees that is in the negative z direction .

Explanation: