Physics, asked by TheAishtonsageAlvie, 1 year ago

if the magnitude of sum of two vectors is equal to the magnitude of difference of the two vectors the angle between these vector is

a) 90 b) 45 c) 180 d)0

Answers

Answered by Bunti360
50

Here is the solution :

let the two vectors be a and b,

According to the question,

|a-b| = |a+b|,

from parallelogram law of vectors, we know that,

|p±q| = √(p² + q² ± 2pq cos ∆)

where, ∆ = angle between the vectors p and q,

=> √(a²+b²+2abcos∆) = √(a²+b²-2abcos∆)

squaring on both sides and cancelling a and b both sides,

=> 2abcos∆ = -2abcos∆

=> 4abcos∆ = 0,

|a| ≠ |b| ≠ 0,

=> cos∆ = 0,

=> ∆ = odd integral multiples of 90°,

=> ∆ = 90°, 270°...

since 270° isn't in the options given, (a) 90° will be the correct answer.

therefore , the angle between the 2 vectors is 90°.

Hope you understand, Thanking you,

Bunti 360!


sdevikrishna00855: Let the magnitude of vector A and B be 'a' and 'b' respectively. The angle b/w them is x
sdevikrishna00855: The sum of a and be is √a2+b2+2abcosx difference in their magnitudes is a-b from both of this √a2+b2+2abcosx= a-b squaring both sides we get 2ab(cosx + 1) = 0 cosx+1 =0 cosx = 1 therefore x = 0°
Bunti360: |a-b| is wrong, If what you did is right, then, cos x = -1 not +1.
sdevikrishna00855: Ohh my mistake. But by this cost=-1 we get the value of x as 180° right..?
Answered by sristi200415
7

Answer:

Explanation:

The correct answer is 180°...

Plz refer the attachment below. ...

Attachments:
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