Physics, asked by tabasum419, 9 months ago

If the magnitudes of two vectors A and B are 3 and 4 respectively and their scalar product is 6 find the angle between them and also find their vector product

Answers

Answered by zarabhangar
4

Answer:

60° , 6√3

Explanation:

for angle

A.B= ABCOSΦ

6÷12=COSΦ

Φ= COS INVERSE (1÷2)

Φ=60°

VECTR PRODUCT

A×B=ABSIN60

A×B = 4×3√3/2

A×B=6√3

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