If the mass of m2 is reduced by 50% and the force exerted by m1 on m2 is 20n what is the force exerted by m 2 on m1 by universal law of gravitation
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Original gravitational force = 20 N
New gravitational force = (20 - 20 × 50%) N = 10 N
New gravitational force = (20 - 20 × 50%) N = 10 N
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Answer:
F2= 20 ,F1 = F2;
M2 = 20 SO, M1 = M2;
FINALE ANSWER IS 20
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